Question

The ratio in which i+2j+3k divides the jion of -2i+3j+5k and 7i-k is​

Answer 1

Step-by-step explanation:

Given The ratio in which i+2j+3k divides the jion of -2i+3j+5k and 7i-k is​

• Given The ratio in which i+2j+3k divides the jion of -2i+3j+5k and 7i-k is    
• Now i + 2j + 3k will be (1, 2, 3)
• Also – 2 I + 3 j + 5 k will be (- 2, 3, 5)
• Now 7 I – k will be (7, 0, - 1)
• Now equating we get 7x – 2 / x + 1
• So 7 x – 2 = x + 1
• Or 6 x = 3
• Or x = 3 / 6 = 1 / 2
• Therefore the ratio will  be 1 : 2

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https://brainly.in/question/1523941