the ratio in which perpendicular through (4,1) divides the line joining (2,-1) (6,5) is
Answers
Answered by
0
Substitute the values x₁=2,x₂=6,y₁=-1and y₂=5 and (x,y) =(4,1) in section formula .
(x,y) = (x₁m₂+x₂m₁/m₁+m₂,y₁m₂+y₂m₁/m₁+m₂) where m₁:m₂ is the required ratio.
(4,1)=(2m₂₊6m₁/m₁₊m₂,5m₁-m₂/m₁₊m₂)
2m₂₊6m₁/m₁₊m₂=4
2m₂+6m₁=4m₁+4m₂
4m₁-2m₁=6m₂-4m₂
2m₁=2m₂
m₁/m₂=2/2
m₁/m₂=1
Therefore m₁:m₂=1:1
Hope this helps you.
If it hep you please mark it as best............ :-)
(x,y) = (x₁m₂+x₂m₁/m₁+m₂,y₁m₂+y₂m₁/m₁+m₂) where m₁:m₂ is the required ratio.
(4,1)=(2m₂₊6m₁/m₁₊m₂,5m₁-m₂/m₁₊m₂)
2m₂₊6m₁/m₁₊m₂=4
2m₂+6m₁=4m₁+4m₂
4m₁-2m₁=6m₂-4m₂
2m₁=2m₂
m₁/m₂=2/2
m₁/m₂=1
Therefore m₁:m₂=1:1
Hope this helps you.
If it hep you please mark it as best............ :-)
2092000:
no. i am not getting 1:5
please try once again
i dont have that option
are you from SSC
I mean from TS or AP syllabus
I have edited please check the answer
Similar questions