The ratio in which the line 2y – 3x = 8 divides the line segment joining the points (1, 4) and (– 2, 3) is:-
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༒︎♡︎ EXPLANATION ♡︎༒︎
Ratio in which the line 2y - 3x = 8 divides the line segment joining the points (1, 4) and (-2,3).
As we know that,
Section formula for internal division.
⟹m+nmx2+nx1 , m+nmy2+ny1[/tex]
Using this formula in the equation, we get.
Let the line 2y - 3x = 8 divides the line segment in the ratio = k : 1.
⇒ x₁ = 1 and y₁ = 4.
⇒ x₂ = - 2 and y₂ = 3.
⇒ m = k and n = 1.
Put the values in the equation, we get.
Equation of line : 2y - 3x = 8.
Put the values of x and y in the equation of line, we get.
Ratio = 3 : 4.
Answer:
3:4
Step-by-step explanation:
Given that the ratio in which the line 2y - 3x = 8 divides the line segment joining the points (1, 4) and (-2, 3) in ratio k:1.
Used formula: (mx2 + nx1)/(m + n), (my2 ny1)/(m + n)
Where, x 1 = 1, x2 = -2, y1 = 4, y2 = 3, m = k, n = 1
Substitute the values,
→ (-2k + 1)/(k + 1), (3k + 4)/(k + 1)
Equation: 2y - 3x = 8
→ 2 × (3k + 4)/(k + 1) - 3 × (-2k + 1)/(k + 1) = 8
→ (6k + 8)/(k + 1) + (6k - 3)/(k + 1) = 8
→ 6k + 8 + 6k - 3 = 8(k + 1)
→ 12k + 5 = 8k + 8
→ 12k - 8k = 8 - 5
→ 4k = 3
→ k = 3/4
Hence, the ratio is 3:4.