Math, asked by DrithiFranklin, 1 day ago

the ratio in which the line segment is joining A(2,7) B(4,-7) is divided by x-axis is the ratio in which the line segment is joining A(2,7) B(4,-7) is divided by x-axis is

Answers

Answered by tagorbisen
1

Answer:

Ncert exemplar solutions

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Mathematics

Science

Chapters in Mathematics Exemplar Problems - class 10

Exercises in Coordinated Geometry

Question 5

In what ratio does the x–axis divide the line segment joining the points (– 4, – 6) and (–1, 7)? Find the coordinates of the point of division.

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Let the ratio in which x-axis divides the line segment joining (–4, –6) and (–1, 7) = 1: k.

Then,

x-coordinate becomes (-1 – 4k) / (k + 1)

y-coordinate becomes (7 – 6k) / (k + 1)

Since P lies on x-axis, y coordinate = 0

(7 – 6k) / (k + 1) = 0

7 – 6k = 0

k = 7/6

Therefore, the point of division divides the line segment in the ratio 6 : 7.

Now, m1 = 6 and m2 = 7

By using section formula,

x = (m1x2 + m2x1)/(m1 + m2)

= (6(-1) + 7(-4))/(6+7)

= (-6-28)/13

= -34/13

So, now

y = (6(7) + 7(-6))/(6+7)

= (42-42)/13

= 0

Hence, the coordinates of P are (-34/13, 0)

Step-by-step explanation:

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Answered by мααɴѕí
1

Answer:

x-coordinate becomes (-1 – 4k) / (k + 1)

y-coordinate becomes (7 – 6k) / (k + 1)

Since P lies on x-axis, y coordinate = 0

(7 – 6k) / (k + 1) = 0

7 – 6k = 0

k = 7/6

Therefore, the point of division divides the line segment in the ratio 6 : 7.

Now, m1 = 6 and m2 = 7

By using section formula,

x = (m1x2 + m2x1)/(m1 + m2)

= (6(-1) + 7(-4))/(6+7)

= (-6-28)/13

= -34/13

So, now

y = (6(7) + 7(-6))/(6+7)

= (42-42)/13

= 0

Hence, the coordinates of P are (-34/13, 0)

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