Question

The ratio in which the line segment joining P(a,b) and Q(c,d) is divided by x-axis is​

Answer 1

Answer:

Using the section formula, if a point (x,y) divides the line joining the points (x

1

,y

1

) and (x

2

,y

2

) in the ratio m:n, then (x,y)=(

m+n

mx

2

+nx

1

,

m+n

my

2

+ny

1

)

Substituting (x

1

,y

1

)=(3,4) and (x

2

,y

2

)=(−2,−1) in the section formula, we get the point (

m+n

m(−2)+n(3)

,

m+n

m(−1)+n(4)

)=(

m+n

−2m+3n

,

m+n

−m+4n

)

As the point lies on x - axis, we have the y -coordinate=0.

=>m+n

−m+4n=0

=>m=4n or m:n=4:1