Question

the ratio lengths of the parallel sides of a trapezium is 4 : 1. the distance between them is 10cm. it the area of the trapezium is 500cm^2. find the lengths of the parallel sides.​

Answer 1

Answer:

$area \: of \: trapezium \: = \frac{1}{2}(a + b)h \\ area \: = 500 {cm}^{2} \\ h = 10cm \\ \frac{1}{2} (x + 4x)10cm = 500 {cm }^{2} \\ \frac{1}{2} (5x)10cm = 500 {cm}^{2} \\ (5x)5cm = 500 {cm}^{2} \\ 5x = \frac{500 {cm}^{2} }{5cm} \\ 5x = 100cm \\ x = \frac{100cm}{5} = 20cm \\ x = 20cm \\ 4x = 4(20cm) \\ 4x = 80cm$

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