Question

the ratio of 2 adjacent angles of a parallelogram is 3:2 then find these angles
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Answer 1

Answer:

Step-by-step explanation:

Let the measures of two adjacent angles, ∠A and ∠B, of parallelogram ABCD are in the ratio of 3:2.

Let ∠A = 3x and ∠B = 2x

We know that the sum of the measures of adjacent angles is 180º for a parallelogram.

∠A + ∠B = 180º

3x + 2x = 180º

5x = 180º

∠A = ∠C = 3x = 108º (Opposite angles)

∠B = ∠D = 2x = 72º (Opposite angles)

Thus, the measures of the angles of the parallelogram are 108º, 72º, 108º, and 72º.

Answer 2

Step-by-step explanation:

Since in Parallelogram the sum of two adjacent angles is 180

Let A &B are two adjacent angles then ,

A=3x & B=2x

A+B = 180

5x = 180

x = 36

So, A = 108 & B = 72 Answer