The ratio of a 2 digit number to the number obtained by reversing its digits is 5:17. if the sum of its digits is 6, find the number. use only one variable. i will thank i will brainlist if it is right please fast please answer i will give extra points please please please please please please please please please please please please please please please please please please please please please please
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fogheyfjh good question good question.
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Let the ten's place digit for original number be x .
Then Unit's place digit will be ( 6 - x ) as sum of digits is 6 .
Number = 10x + 6 - x = 9x + 6
∵ { Multiplying the ten's place by 10 }
After reversing the digits :
Ten's place = ( 6 - x )
Unit's place = x
Number obtained by reversing the digits = 10 ( 6 - x ) + x
∵ { Multiplying the ten's place by 10 }
= 60 - 10x + x = 60 - 9x
According to question,
( 9x + 6 ) / ( 60 - 9x ) = 5 / 17
17( 9x + 6 ) = 5( 60 - 9x )
153x + 102 = 300 - 45x
198x = 198
x = 1
Required number = 10( x ) + ( 6 - x )
= 10 + ( 6 - 1 )
= 10 + 5
= 15
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