Question

the ratio of adjacent sides of a rectangle is 5:2 if perimeter of rectangle is breadth of rectangle​

Answer 1

Let, the adjacent side(breadth & length) of the rectangle be 5x and 12x.

We know that, perimeter of rectangle = 2(l + b)

The perimeter of the rectangle = 34 cm

By the problem,

2(l + b) = 34

=》2(12x + 5x) = 34

=》2 × 17x = 34

=》34x = 34

=》x = 1

The value of x = 1 cm

So the value of length = 12 × 1= 12 cm

The value of breadth = 5 × 1= 5 cm

Now, the formula for, the diagonal of a rectangle = root (l² + b²)

By using this formula,

The diagonal of the rectangle = root (12² + 5²)

= root (144 + 25)

= root (169)

= root (13²)

= 13 [ as when a squared number comes out from a root, square is removed]

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Answer 2

Step-by-step explanation:

let the adjacent side(breath & length) of the rectangle be

5× and 12×.

we know that parameter of rectangle =( l + b)

The parameter of the rectangle=34 cm

By the problem,

2×( l+b ) = 34 cm

= 2 ( 12× + 5× ) =34

= 2x =34

34× =34

x=1

The value of x = 1 cm

so,the value of length =12 ×1= 12 cm

The value of breadth = 5× 1 =5 cm

now, the formula for the diagonal of a rectangle = board (1² + b²)

by using this formula,

The diagonal of the rectangle =board

(12²+ 5²)

board ( 144+ 25)

board (169)

board (13² )

= 13 (as when a squared number comes out from a board, square is removed)