Math, asked by sreemitha, 4 months ago

The ratio of age A and B is 13:7. The difference of their ages is 36 years. what was the ratio of their ages 6 years before?​

Answers

Answered by rishabhyadav004
1

Answer:

72:36

Step-by-step explanation:

the ratio of ages now with difference of 36

13 x 6 : 7 x 6

78:42

ratio of ager 6 years before

72:36

Answered by Anonymous
0

The ratio of their ages 6 years before is 2:1

Given : The ratio of age A and B is 13:7. The difference of their ages is 36 years.

To find : The ratio of their ages 6 years before.

Solution :

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the ratio of their ages 6 years before)

Let, their ages = 13x years and 7x years

(obtained from the ratio 13:7)

Difference of their ages = 13x - 7x = 6x years

According to the data mentioned in the question,

6x = 36

x = 36/6

x = 6

Present age of A = (13 × 6) = 78 years

Present age of B = (7 × 6) = 42 years

6 years before :

  • Age of A = (78-6) = 72 years
  • Age of B = (42-6) = 36 years

The ratio of their ages 6 years before = 72:36 = 2:1

(This will be considered as the final result.)

Hence, the ratio of their ages 6 years before is 2:1

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