Math, asked by mehulpagare0701, 7 months ago


The ratio of ages (in years) of A and B , 9 years ago, was 23:12. The ratio of their ages after 15 years will
be 35:24. What is the ratio of present ages of A and B ?

Answers

Answered by MaIeficent
8

Step-by-step explanation:

Let the present age of A be " x "

And present age of B be " y "

9 years ago:-

Age of A = x - 9

Age of B = y - 9

Given,9 years ago, the ratio was 23 : 12

 \rm \dashrightarrow \dfrac{x - 9}{y - 9}  =  \dfrac{23}{12}

 \rm \dashrightarrow 12(x - 9) = 23(y - 9)

 \rm \dashrightarrow 12x - 108 = 23y - 207

 \rm \dashrightarrow 12x - 23y = -207 + 108

 \rm \dashrightarrow 12x - 23y = -99.....(i)

15 years later:-

Age of A = x + 15

Age of B = y + 15

Given,9 years ago, the ratio was 35 : 24

 \rm \dashrightarrow \dfrac{x + 15}{y + 15}  =  \dfrac{35}{24}

 \rm \dashrightarrow 24(x + 15) = 35(y + 15)

 \rm \dashrightarrow 24x + 360 = 35y + 525

 \rm \dashrightarrow 24x - 35y = 525 - 360

 \rm \dashrightarrow 24x - 35y = 165.....(ii)

Multiplying equation (i) with 2

 \rm \dashrightarrow 2(12x - 23y = -99)

 \rm \dashrightarrow 24x - 46y = -198.....(iii)

Equation (ii) - Equation (iii)

 \rm \dashrightarrow 24x - 35y - 24x + 46y  = 165 + 198

 \rm \dashrightarrow 11y = 363

 \rm \dashrightarrow y = \dfrac{363}{11} = 33

Substituting y = 33 in equation (i)

 \rm \dashrightarrow 12x - 23y = -99

 \rm \dashrightarrow 12x - 23(33) = -99

 \rm \dashrightarrow 12x - 759 = -99

 \rm \dashrightarrow 12x = 759 -99

 \rm \dashrightarrow 12x = 660

 \rm \dashrightarrow x = \dfrac{660}{12} = 55

Therefore:-

Present age of A = 66 years

Present age of B = 33 years

Answered by viny10
27

\huge {\underline {\mathfrak{ \red a \blue n \green \pink s \orange w\purple e\red r\: - }}}

  • Let the present age of A be x

  • And present age of B be y

\underline\bold\blue{9  \: years \:  ago:-}

  • Age of A = x - 9

  • Age of B = y - 9

Given,9 years ago, the ratio was 23 : 12

\rm \dashrightarrow \dfrac{x - 9}{y - 9} = \dfrac{23}{12}</p><p> </p><p>

\rm \dashrightarrow 12(x - 9) = 23(y - 9)

\rm \dashrightarrow 12x - 108 = 23y - 207

\rm \dashrightarrow 12x - 23y = -207 + 108

\rm \dashrightarrow 12x - 23y = -99.....(i)

\underline\bold\pink{15 \:  years \:  later:-}

  • Age of A = x + 15

  • Age of B = y + 15

Given,9 years ago, the ratio was 35 : 24

\rm \dashrightarrow \dfrac{x + 15}{y + 15} = \dfrac{35}{24}</p><p>

\rm \dashrightarrow 24(x + 15) = 35(y + 15)

\rm \dashrightarrow 24x + 360 = 35y + 525

\rm \dashrightarrow 24x - 35y = 525 - 360

\rm \dashrightarrow 24x - 35y = 165.....(ii)

\boxed{Multiplying \:  equation \:  (i) \:  with  \: 2}

\rm \dashrightarrow 2(12x - 23y = -99)

\rm \dashrightarrow 24x - 46y = -198.....(iii)

\underline\bold{Subtract \:  Equation  \: (ii) - Equation \:  (iii)}</p><p>

\rm \dashrightarrow 24x - 35y - 24x + 46y = 165 + 198

\rm \dashrightarrow 11y = 363

\rm \dashrightarrow y = \dfrac{363}{11} = 33

\underline\bold{Substituting \:  y  \: = \:  33 \:  in \:  equation  \: (i)}

\rm \dashrightarrow 12x - 23y = -99

\rm \dashrightarrow 12x - 23(33) = -99

\rm \dashrightarrow 12x - 759 = -99

\rm \dashrightarrow 12x = 759 -99

\rm \dashrightarrow 12x = 660

\rm \dashrightarrow x = \dfrac{660}{12} = 55

\underline\bold\red{Therefore:-}

☞Present age of A = 66 years

☞Present age of B = 33 years


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