Question

the ratio of ages of a father and son is 17:7 respectively. 6 years ago the ratio of their ages was 3:1 respectively. what is the father's present age

Answer 1

let 17x and 7x be the ages of father and son respectively.6 years ago their ages was 17x-6 & 7x-6 and the ratio of that. ages is given as 3:1. then
17x-6/7x-6=3/1
on solving this we get x=3
so the present age of father and son=17x&7x
=17×3. &7×3
=51. &. 21

Answer 2

Answer:

If the ratio of ages of a father and son is 17:7 and 6 years ago the ratio of their ages was 3:1 then the father's present age is 51 years.

Step-by-step explanation:

• The ratio of ages of a father and son is 17:7

• Let the common factor of the ratio be x.

• Hence,  age of the father is 17x.

• Age of the son is 7x.

• 6 years ago, father's age was (17x - 6).

• 6 years ago, the son's age was (7x - 6).

According to the given problem, 6 years ago the ratio of their ages was 3:1

Hence, we can write (17x - 6) : (7x - 6) =  3 : 1 .

(17x - 6) : (7x - 6) =  3 : 1

⇒ $\frac{17x - 6}{7x - 6}$  = $\frac{3}{1}$

by cross multiplication, we can write

 17x - 6 = 3×(7x - 6)

⇒17x - 6 = 21x - 18

⇒ 21x - 17x = 18 - 6

⇒ 4x = 12

⇒ x = 12/4

⇒ x = 3

Hence, 17x = 17 × 3 = 51.

So, father's present age is 51 years.