Math, asked by prachi261105, 1 year ago

the ratio of ages of hina and kanika is 4:3 the sum of their ages is 28 years what is the age of hina

Answers

Answered by Anonymous
43
let there ages = 4x and 3x

atq

4x + 3x=28

7x=28

×= 28/7
×= 4

age of hina = 4×4=16 years

age of kanika=4×3=12. years


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Answered by Anonymous
24
\huge{\mathfrak{Answer \ :-}}
<b>
Let age of Hina = 4x

Age of Kanika = 3x

<b><u>According to Question :-</b></u>

4x + 3x = 28

7x = 28

x = \dfrac{28}{7}

x = 4

So, Hina's age = 4 × 4 = 16 years

Kanika's age = 3 × 4 = 12 years

Hina's age :-

<h1><u>16 years</h1></u>
\huge{\mathfrak{Thanks \ !!}}
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