Question

The ratio of ages of Monu and Sonu is 5:7 . Four years later the ratio of there ages will be 3:4 . Find there present ages . ​

Answer 1

$\huge \boxed{ \fcolorbox{cyan}{grey}{Answer : }}$

____________________________________

$\sf \huge \underline \red{Question}$

The ratio of ages of Monu and Sonu is 5:7 . Four years later the ratio of there ages will be 3:4 . Find there present ages

_____________________________________

$\sf \huge\underline \red{To \: find}$

• present ages

____________________________________

$\sf \huge \underline \red{Given}$

• The ratio of ages of Monu and sonu is 5:7

• Four years later the ratio of there ages will be 3:4 .

_____________________________________

$\sf \huge \underline \red{solution}$

$\rm{⟹ \: let \: ratio \: be \: x}$

$\rm \blue{⟹ \: monu \: ages \: is \: 5}$

$\rm \orange{⟹ \: sonu \: age \: is \: 7}$

$\bf \red{4 \: years \: after \: later \: we \: get}$

$\bf \red{5x + 4 \: and \: 7x + 4}$

Now equation from refer to attachment

Answer 2

$\sf{\huge{\mathfrak{\pink{\underline{Question}}}}}$

• The ratio of ages of Monu and Sonu is 5:7 . Four years later the ratio of there ages will be 3:4 . Find there present ages .

$\sf{\huge{\mathfrak{\pink{\underline{solution}}}}}$

let monu's and sonu's age be 5x and 7x

after 4 years :-

monu's age = 5x + 4

sonu's age = 7x + 4

ATQ:-

$\sf \dfrac{5x + 4}{7x + 4} = \dfrac{3}{4}$

$\sf 4 (5x + 4 ) = 3 ( 7x + 4)$

$\sf 20x + 16 = 21x + 12$

$\sf 16 - 12 = 21x - 20x$

$\sf x = 4$

• putting value of x in the ratio

5x = 5 x 4 = 20 years

7x = 7 x 4 = 28 years

$\sf{\bold{\red{\boxed{monu's age = 20years}}}}$

$\sf{\bold{\red{\boxed{sonu's age = 28years }}}}$

__________________❤