Question

The ratio of ages of Ram and shaym is 2
: 6 and after 5 years the ratio of their
age becomes 6 : 8. What will be their
average age (in years) after 10 years?​

Answer 1

Step-by-step explanation:

ram's age /shyam's age =2/6 ram's age =2x ...shyam's age=6x after 5 years, (2x+5)/(6x+5)= 6/8 16x+40=36x+30 20x=10 x=1/2 present ram's age =2x=1 present shyam's age=6x=3 after 10 years, ram's age=11 and shyam's age=13 avg. of their age=(11+13)/2 avg. of their age=12

Answer 2

Answer: Average age = 12 years

Step-by-step explanation:

Let ram's present age be 2a,

Shaym's present age be 6a

After 5 years their age ratio becomes 6/8

(2a+5) / (6a+5) = 6/8

By cross multiplication,

(2a+5) * 8 = (6a+5) * 6

16a+40 = 36a+30

36a-16a = 40-30

20a = 10

a = 1 / 2

Ram 's present age = 2a = 2*(1/2) = 1 year

Shaym's present age = 6a = 6 *(1/2)= 3 years

Average age after 10 years =

((1+10)+(3+10))/2

= (11+13)/2

= 24/2

= 12 years