Question

The ratio of ages of the father and his son at present is 12:5. The difference of their ages is 28 years. What will be the ratio of their ages after eight years?​

Answer 1

Answer:

The ratio of their ages will be 2:1 after 8 years.

Step-by-step explanation:

Given :-

• The ratio of ages of the father and his son at present is 12:5.
• The difference of their ages is 28 years.

To find :-

• The ratio of their ages after 8 years.

Solution :-

Let the present age of father be 12x years and the present age of son be 5x years.

According to the question,

• The difference of their ages is 28 years.

12x-5x = 28

→ 7x = 28

→ x = 28/7

→ x = 4

Then,

• Present age of father = 12×4 = 48 years
• Present age of son = 5×4 = 20 years.

After 8 years,

★ Father's age = (48+8) = 56 years

★ Son's age = (20+8) = 28 years

Then,

The ratio of their ages after 8 years,

Father's age : Son's age

= 56 : 28

= 2:1

Therefore, after 8 years the ratio of their ages will be 2:1.

Answer 2

Given : The ratio of ages of the father and his son at present is 12:5. The difference of their ages is 28 years.

Answer:

The ratio of their ages after 8 years is 2:1.

Step-by-step explanation:

Let the present age of father and son be 12xyears and 5x years respectively.

❏ According to Question now,

➥ 12x - 5x = 28

➥ 7x = 28

➥ x = 28/7

➥ x = 4 years

Therefore,

• Present age of Father = 12x = 12(4) = 48 years.

• Present age of Son = 5x = 5(4) = 20 years.

⬤ After 8 years the age of father and son will be :

• Age of father = 12x + 8 = 48 + 8 = 56 years.

• Age of son = 5x + 8 = 20 + 8 = 28 years

❍ The ratio of their ages after 8 years will be :

᠉ 56/28

᠉ 2/1

Therefore,The ratio their ages after 8 years will be 2:1.