The ratio of ages of two persons is 4 : 7 and one is 30years older than the other. find the sum of their ages.
Answers
Answered by
4
hello friend!!
here's ur answer...
let the ages of 2 persons be 4x and 7x.
if one of the person is 30yrs older than other then:-
7x-4x=30
3x=30
x=30/3
x=10
hence, age of 1st person=4x
=4×10
=40yrs
age of 2nd person=7x
=7×10
=70yrs
hope this helps...
here's ur answer...
let the ages of 2 persons be 4x and 7x.
if one of the person is 30yrs older than other then:-
7x-4x=30
3x=30
x=30/3
x=10
hence, age of 1st person=4x
=4×10
=40yrs
age of 2nd person=7x
=7×10
=70yrs
hope this helps...
Answered by
1
Given:
The ratio of the ages of two persons is 4:7 and one is 30 years older than the other.
To Find:
The sum of their ages is?
Solution:
The given problem can be solved using simple algebra.
1. The ratio of the ages of two persons is 4:7.
2. Let the ages of the two persons be 4x and 7x respectively.
3. One of them is 30 years older than the other, the algebraic equation will be,
=> 7x = 4x + 30,
=> 7x - 4x = 30,
=> 3x = 30,
=> x = 30/3,
=> x = 10.
4. The ages of the two persons are 4x ( 4*10) and 7x (7*10),
=> The ages of the two persons are 40 and 70.
=> The sum of their ages is 40 + 70 = 110.
Therefore, the sum of the ages of two people is 110.
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