Math, asked by omkardhas72, 9 months ago

The ratio of ages today of Vinayak and Manish is 10:9. Eight years ago the
ratio of their ages then was 6:5. Find their ages today:​

Answers

Answered by adyagarg
1

Answer:

Vianyak=20

Manish= 18

Step-by-step explanation:

Let the ages of Vinayak and manish be 10x and 9x

ATQ,

10x-8/9x-8 = 6/5

5(10x-8) = 6(9x-8)

50x-40=54x-48

-40+48=54x-50x

8=4x

x=8/4=2

Vinayak's present age=2×10=20

Mainsh's present age=2×9=18

Answered by samridhi2207
0

Answer:

Let the present age of Vinayak and manish is 10x and 9x.

After 8 years -

Age of Vinayak =10x+8

Age of Manish = 9x+8

A/q,

10x+8/9x+8 = 6/5

5(10x+8) = 6(9x+8)

50x + 40 = 54x+ 48

54x - 50x = 48 - 40

4x = 8

x = 8/4

x = 2

present age of vinayak = 10 * 2

= 20 years

present age of manish = 9 * 2

= 18 years

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