The ratio of alcohol and water in vessels A and B are 3:7 and 4:11, respectively. Five litres and 71 litres
solutions from vessels A and B, respectively are mixed in vessel C. What is the ratio of water and alcohol in
the solution in C?
Answers
Step-by-step explanation:
The ratio in vessel one is 3:7
so 3+7=10
alcohol(in litres)=3/10×5=3/2
water(in litres)=7/10×5=7/2
SolutionA(in litres)=3/2+7/2=10/2=5litres
The ratio in vessel two is 4:11
so 4+11=15
alcohol(in litres)=4/15×71=18.93
water(in litres)=11/15×71=52.06
SolutionB(in litres)=18.93+52.06=70.99
SolutionC(in litres)=SolutionA + SolutionB
=5+70.99
=75.99litres
HOPE IT HELPS!!!!!!!!!
Given : The ratio of alcohol and water in vessels A and B are 3:7 and 4:11, respectively.
5 litres and 7 litres solutions from vessels A and B. respectively are mixed in vessel C.
To Find : Ratio of water and alcohol in the solution in C?
Solution:
The ratio of alcohol and water in vessels A = 3 : 7
Solution Taken = 5 litre
=> Alcohol = ( 3/10) * 5 = 1.5 litre
Water = 5 - 1.5 = 3.5 litre
The ratio of alcohol and water in vessels B = 4 : 11
Solution Taken = 7 litre
=> Alcohol = ( 4/15) *71 =284/15 litre
Water = ( 11/15) *71 = 781/15 litre
Total water = 3.5 + 781/15 = 7/2 + 781/15
= ( 105 + 1562) /30
= ( 1667)/30
Total alcohol = 1.5 + 284/15 = 3/2 + 284/15
= ( 613) / 30
ratio of water and alcohol in the solution in C
( 1667)/30 : ( 613) / 30
= 1667 : 613
ratio of water and alcohol in the solution in C = 1667 : 613
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