Question

The ratio of amounts of H2S needed to precipitate all the metals ions from 100ml of 1M Agno3 and 100ml of 1M CuSO4 is

Answer 1

2AgNO3 + H2S → Ag2S + 2HNO3
Ratio: 1H2S : 2AgNO3

CuSO4 + H2S → CuS + H2SO4
Ratio:1H2S : 1CuSO4

Answer 2

Given : Volume of AgNO3 = 100 ml

Volume of CuSO4 = 100ml

Conc.of AgNO3 = 1M

Conc. Of CuSO4 = 1M

To Find : Ratio of amount of H2S to AgNO3

and, ratio of amount of H2S to CuSO4

Solution :

- When AgNO3 reacts with H2S the following reaction occurs:-

2AgNO3 + H2S ---> 2Ag2S + 2HNO3

- After balancing the equation we come to know that,

1 mole of H2S reacts with 2 mole of AgNO3

- So, to precipitate all the metal ions from 100 ml of 1M AgNO3 the ratio of amount of H2S required is,

1 H2S : 2AgNO3

- When CuSO4 reacts with H2S the reaction occurred is mentioned below:-

CuSO4 + H2S ---> CuS + H2SO4

- Here, 1 mole of H2S reacts with 1 mole of CuSO4

- So, to precipitate all the metal ions from 100 ml of 1M CuSO4 the ratio of amount of H2S required is,

1 H2S : 1 CuSO4

- Hence, The answer is 1:2 and 1:1 .