Math, asked by junnu77, 8 months ago

The ratio of an interior angle to an exterior angle of a regular polygon is 5 : 2. What is the number of sides of the polygon ?​

Answers

Answered by Anonymous
3

Answer:

\huge\underline\bold {Answer:}

Interior angle of polygon of n sides = (n – 2) × 180°/n

Exterior angle of a polygon of n sides = 360°/n

Given, (n – 2) × 180°/n : 360°/n = 5 : 2

=> (n – 2) × 180°/n × 360°/n = 5/2

=> (n – 2)/2 = 5/2

=> 2(n – 2) = 10

=> 2n – 4 = 10

=> 2n = 14

=> n = 7.

Therefore number of sides of the polygon is 7.

Answered by Anonymous
5

Answer:

\bigstar QUESTION :-\bigstar

The ratio of an interior angle to an exterior angle of a regular polygon is 5 : 2. What is the number of sides of the polygon ?

\bigstarGIVEN :-\bigstar

Ratio of an interior and exterior angle of a regular polygon is 5:2 respectively.

\bigstarTO FIND :-\bigstar

The no. of sides of the polygon.

\bigstar SOLUTION :- \bigstar

We know that,

  • Interior angle of a polygon having n sides :-

 \sf  =  \frac{(n - 2 )\times 180\degree}{ n}  \\  \sf

And,

  • Exterior angle of a polygon having n sides :-

  \sf \:  =  \frac{360 \degree}{n}  \\

Now,

According to the question,

We can say that,

 \to \sf \:  \frac{(n - 2) \times 180 \degree}{n}  \ratio \:  \frac{360 \degree}{n}  = 5 \ratio2 \\  \implies \sf \frac{(n - 2) \times  \cancel{180} \degree}{ \cancel{n}}  \times  \frac{ \cancel{n}}{ \cancel{360} \degree}  = 5 \ratio2 \\  \sf \implies \sf \:  \frac{(n - 2)}{2}  =  \frac{5}{2}  \\  \sf \implies \: 2(n - 2) = 5 \times 2 \\  \sf \implies \: 2n - 4 = 10 \\  \sf \implies \: 2n = 10 + 4 \\  \sf \implies \: 2n = 14  \\  \sf \implies \: n =  \frac{ \cancel{14}}{ \cancel2}  \\  { \underline{ \boxed{\bf \therefore \: n = 7}}}

Hence,

  • No. of sides of polygon is 7.
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