The ratio of an Isoceles 7:6:7, find the base angles
Isoceles (2 sides equal that the base)
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Taking 7:6:7 as ratio of angles.
Let the angles be 7x, 6x, 7x.
Now sum of all angles is 180 in a ∆.
So, 7x+6x+7x=180°
20x=180°
x=180/20=9°
Now, base angles are equal, so they are both 7x.
Hence, ans is 7x=9×7=63°
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