The ratio of areas of incircle and circumcircle of an equilateral triangle will be ?
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Answered by
19
Let the side length of the equilateral triangle = x
Area of incircle = (1/12) πx²
Area of circumcircle = (1/3) πx²
so ratio circumcircle area / incircle area = (1/3) / (1/12) ... [b/c the πx² bits cancel]
= (1/3) * (12/1)
= 4/1
so area circumcircle : area incircle = 4 : 1
Answered by
2
1/4
in case of equilateral triangle, however, the ratio r/R can be found and is =1/2
so area is π *radius*radius
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