the ratio of atoms present in 4g of magnesium and 4g of sulphur
Answers
The correct ratio is - 4:3.
Number of moles = weight/atomic weight
Atomic weight of magnesium = 24
No. of moles of magnesium (Mg) = 4/24 = 0.16
Atomic weight of sulphur = 32
No. of moles of Sulphur (S) = 4/32 = 0.12
Therefore, the ratio of 4 gm of Magnesium to 4 gm of Sulphur is = 0.16:0.12, which can further be simplified without decimals as 4:3.
The Answer of your question is “4:3”
It is easy to find through the number of moles formula which is equal to weight/atomic weight.
We know that the atomic of magnesium is equal to 24 u
And the atomic weight of sulphur is equal to the 32 u
So the number of moles for magnesium will be = 4/24= 0.16 (4g as said in question)
Also the number of moles for the sulphur =4/32 = 0.12
Hence this makes the ratio 4g of both magnesium and sulphur like that 0.16:0.12 the simplification of which will give 4:3 .
You can also right the ratio in sulphur and magnesium form as 3:4