the ratio of balls in three boxes is 6:8:9. in what ratio should the balls in the second and third boxes be increased, so that final ratio becomes 1:3:4
Answers
Given : ratio of balls in three boxes is 6:8:9
To find : in what ratio should the balls in the second and third boxes be increased, so that final ratio becomes 1:3:4
Solution:
Let say initially balls are
6B , 8B & 9B
Total Balls = 27B
Let say balls are increased by Bk & mB (ratio k : m )
Then Balls would be
6B , B(8 + k) , B(9 + m)
Final Ratio
1 : 3 : 4
6B/B(8 + k) = 1/3
=> 18 = 8 + k
=> k = 10
6B/B(9 + m) = 1/4
=> 24 = 9 + m
=> m = 15
k : m = 10 : 15
=> k : m = 2 : 3
balls in the second and third boxes be increased by 2 : 3 Ratio
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The ratio is 2 : 3
Step-by-step explanation:
Given
The final ratio is 1 : 3 : 4
Initial ratio is 6 : 8 : 9
Scaling up the final ratio we get
1 : 3 : 4 is same as 6 : 18 : 24
Initial ratio in 2nd and 3rd boxes = 8 : 9
Final ratio = 18 : 24
So balls in the 2nd and 3rd boxes have been increased by 10 and 15 respectively
Thus, the ratio in which they have been increased
= 10/15
= 2/3
Hope this answer is helpful.
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