The ratio of balls in three boxes is 6:8:9. In what ratio should the balls in the second and third boxes be increased, so that the final ratio becomes
1:3:4?
Answers
Answer:
2:3 *
Step-by-step explanation:
initial ratio = 6:8:9 , final ratio = 1:3:4
assuming initial constant ratio as '1' & so then no. of balls In each box are 6,8 & 9 respectively.
since there is no change in the no. of balls in the 1st box so despite increase in no. of balls in 2nd & 3rd , it will remain same in 1st box .
now assuming new constant ratio as y .
after increase in no. of balls in 2nd & 3rd box
,balls in 1st box 1y = 6 => y = 6
3y = 3(6) = 18 & 4y = 4(6) = 24
increase of no.of balls in 2nd box = 18-8
= 10 & in 3rd box = 24 - 9 = 15
required ratio = 10 : 15 = 2:3
Given : ratio of balls in three boxes is 6:8:9
To find : in what ratio should the balls in the second and third boxes be increased, so that final ratio becomes 1:3:4
Solution:
Let say initially balls are
6B , 8B & 9B
Total Balls = 27B
Let say balls are increased by Bk & mB (ratio k : m )
Then Balls would be
6B , B(8 + k) , B(9 + m)
Final Ratio
1 : 3 : 4
6B/B(8 + k) = 1/3
=> 18 = 8 + k
=> k = 10
6B/B(9 + m) = 1/4
=> 24 = 9 + m
=> m = 15
k : m = 10 : 15
=> k : m = 2 : 3
balls in the second and third boxes be increased by 2 : 3 Ratio
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