The ratio of balls in three boxes is 6:8:9. In what ratio should the balls in the second and third boxes be increased, so that the final ratio becomes
1:3:4?The ratio of balls in three boxes is 6:8:9. In what ratio should the balls in the second and third boxes be increased, so that the final ratio becomes
1:3:4?
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If you want more math challenges try the new PBS MATHLINE MATH ... The sum of the three digit answer will always be 18! ... Always choose a so that it larger than the sum of b and c.
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The best way to approach this problem is to work backwards. The final ratio is 1:3:4. To make this answer more concrete, let's imagine that there are white balls, red balls, and black balls. This means that for 1 white ball, there will be 3 red balls, and 4 black balls. One important thing to note about ratios is that they can be scaled up:
This means that 1:3:4=6:18:24. Scaling this ratio is useful because it allows us to consider how we can get the final ratio to be 1:3:4, without changing the number of white balls, as per the requirements of the question. This seems to be the approach that you have took.
We need to go from
6 white balls, 8 red balls, and 9 black balls
to
6 white balls, 18 red balls, and 24 black balls
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