Question

The ratio of base radius and height of a cone is 3:4. If the cost of smoothening the
curved surface area at 5 paise per 1 sq.cm is Rs.115.50, then find the volume of liquid
contained in it (in lit).​

Answer 1

Answer:

i liter milk

Step-by-step explanation:

Answer 2

The volume of cone is 12936 cubic.cm.

Step-by-step explanation:

The ratio of base radius and height of a cone is 3:4.

Let the ratio be x

So, Radius of cone = 3x

Height of cone = 4x

Curved surface area of cone = $\pi r \sqrt{h^2+r^2}$

So, Curved surface area of cone = $\frac{22}{7} \times 3x \sqrt{(3x)^2+(4x)^2}$

Cost of 1 sq. cm = 5 paisa =Rs. 0.05

Cost of smoothening the surface area of cone = Rs.115.50

Area of cone =$\frac{115.50}{0.05}=2310 cm^2$

So, $\frac{22}{7} \times 3x \sqrt{(3x)^2+(4x)^2}=2310\\x=7$

So, Radius = 3x = 3(7)=21 cm

Height of cone = 4x=4(7)= 28 cm

Volume of cone = $\frac{1}{3} \pi r^2 h =\frac{1}{3} \times \frac{22}{7} \times 21^2 \times 28=12936cm^3$

Hence The volume of cone is 12936 sq.cm.

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