Question

The ratio of boys to girls in a school is 3:2, if there are 398 girls, find the number of boys in the school.

Answer 1

Answer:

Let there be 100 students.

Then number of boys =

5

3

×100=60

Number of girls =

5

2

×100=40

Total scholarship holders =20 % of 60 + 30 % of 40=

100

20

×60+

100

30

×40 = 12+12=24

Number of students without scholarship =100−24=76

∴% of students without scholarship =

100

76

×100=76 %

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Answer 2

Given :

• The ratio of boys to girls in a school is 3:2.

• The number of girls is 398.

To find :

• The number of boys in the school.

Solution :

It is given that the ratio of boys to girls in a school is 3:2

Consider the no. of boys and girls in the school as 3x and 2x respectively.

We know that the no. of girls present in the school is 398

$\implies \sf 2x = 398$

$\implies \sf x = \dfrac{398}{2}$

$\implies \sf x = 199$

Now, to find the no. of boys in the school :-

→ The number of boys in the school = 3x

→ Number of boys in the school = 3 × 199

→ Number of boys in the school = 597

There are 597 boys in the school.

KNOWLEDGE BYTES :-

ALGEBRAIC EXPRESSIONS AND EQUATIONS :-

Those expressions that contains terms with constants and variables connect by mathematical operations are known as algebraic expressions.

An algebraic expression becomes an equation when there is an equal sign along with LHS and RHS