The ratio of C,H and O is C6H1206 is
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% carbon in C6H12O6 = 72.06 × 100 % = 40.0 % by mass. 180.18 Similarly, the percentage of hydrogen and oxygen can be calculated as follows: 1 mole of H atoms weighs 1.01 g and there are 12 moles of H atoms in 1 mole of glucose, so the mass of hydrogen in 1 mole of glucose = 12 × 1.01 g = 12.12 g.
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