Question

The ratio of closed packed atoms to tetrahedral holes in cubic close packing is:
(A)1:1

(B)1:2

(C)1:3

(D)2:1

Answer 1

B- 1:2
If the no of atom in a closed packing is n
Then the no of tetrahedral voids is 2n
Whereas no of octahedral voids is n

Answer 2

Answer:

1:2

Explanation:

Here by closed packed atom it means the number of atom per unit cell = $\frac{1}{8}$ ×8 + 6 × 1/2 = 4

and by tetrahedral holes it means tetrahedral voids and we know that there are 8 tetrahedral voids (each at 1/4th position of body diagonals).

Hence the ratio is 4:8 = 1:2

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