Question

the ratio of contributions made by the electric field and magnetic field components to the intensity of an electromagnetic wave is-??quora​

Answer 1

Electrical energy density in electric field, [math]u_E = \frac12 \epsilon_0 E^2[/math] ... The speed of light in vacuum is given by,. Let us first see how in an electromagnetic wave the electrical and magnetic ... It is further true for an EM wave traveling in space that the ratio of E and H is 377 ohms, the impedance of free space.

Answer 2

Answer:

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Explanation:

The intensity of an electromagnetic wave is given by:

I=Uavc

here, Uav is the average energy and c is the speed of light.

The average energy in terms of the electric field is written as:

Uav=21εoEo2

Average energy in terms of magnetic field:

Uav=21μoBo2

We know that, Eo=cBo and c=μoεo1

∴Uav (electric field)=21εo×μoεo1Bo2

⇒21μoBo2

Since the energy due to electric and magnetic field is same. so, both will have the same contribution to the intensity.

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