Question

The ratio of corresponding side of similar triangles is 3:5then find the ratio of their areas

Answer 1

Answer:

let,

∆ABC~∆PQR,

AB/PQ=BC/QR=AC/PR=3/5...... corresponding sides of a similar triangles and given

A(∆ABC)/A(∆PQR)=AB^2/PQ^2...... theorem of areas of two similar triangles

A(∆ABC)/A(∆PQR)=3^2/5^2=9/25

the ratio of their areas is 9/25