The ratio of corresponding sides of two similar triangles ΔABC
and ΔPQR is 3:5, then find the ratio of the perimeters of the two
triangles.
Answers
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1
Step-by-step explanation:
Since the areas of two similar triangles are in the ratio of the squares of the corresponding altitudes.
∴
Area(△PQR)
Area(△ABC)
=
PS
2
AD
2
⇒
Area(△PQR)
Area(△ABC)
=(
9
4
)
2
=
81
16
[∵AD:PS=4:9]
⇒
Area(△PQR)
Area(△ABC)
=
81
16
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