Math, asked by sruthivankas, 1 month ago

The ratio of cost of two articles was 13:15.4 years later when the cost of the first had risen by Rs. 14
and that of the second by 10%, the ratio of their cost become 14. 11, what is their original cost?​

Answers

Answered by dualadmire
11

Given:

The initial ratio of the numbers= 13:15

The final ratio = 14:11

Cost of first article is raised by Rs. 14

The cost of second article is raised by 10%.

To find:

The original cost of the articles.

Solution:

Let the original numbers be 13x and 15x.

Cost of first article is raised by Rs. 14.

Let the final cost be 14y and 11y.

13x + 14 = 14y- equation 1

15x + 10% of 15x = 11y

15x + 1.5x = 11y

16.5x = 11y

y = 16.5x /11

Put this value in equation 1:

13x + 14 = 14*16.5x/11

13x + 14 = 21x

21x- 13x = 14

8x = 14

x = 14/ 8

x = 1.75

Cost of first article = 13x = Rs. 22.75

Cost of second article = Rs. 26.25

Therefore the original cost of articles is Rs. 22.75 and Rs. 26.25.

Answered by pulakmath007
4

SOLUTION

GIVEN

  • The ratio of cost of two articles was 13 : 15

  • 4 years later when the cost of the first had risen by Rs. 14 and that of the second by 10%

  • The ratio of their cost become 14 : 11

TO DETERMINE

The original cost

EVALUATION

Here it is given that the ratio of cost of two articles was 13 : 15

Let first article cost Rs. 13x and second article costs Rs. 15x

Now it is stated that 4 years later when the cost of the first had risen by Rs. 14 and that of the second by 10%

So the cost of first article becomes

= Rs. ( 13x + 14 )

The cost of second article becomes

 \displaystyle \sf{ = Rs. \:  \: 15x \:  \times  \:  \frac{110}{100} }

 \displaystyle \sf{ = Rs. \:  \: 16.5x  }

So by the given condition

 \displaystyle \sf{(13x + 14):  \: 16.5x   = 14 : 11}

 \displaystyle \sf{ \implies \:  \frac{13x + 14}{16.5x} =  \frac{14}{11} }

 \displaystyle \sf{ \implies \:  231x = 143x + 154 }

 \displaystyle \sf{ \implies \:  88x = 154 }

 \displaystyle \sf{ \implies \:  x = 1.75 }

Hence

Original cost of first article

= Rs. ( 13 × 1.75 )

= Rs. 22.75

Original cost of second article

= Rs. ( 15 × 1.75 )

= Rs. 26.25

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