The ratio of cost of two articles was 13:15.4 years later when the cost of the first had risen by Rs. 14
and that of the second by 10%, the ratio of their cost become 14. 11, what is their original cost?
Answers
Given:
The initial ratio of the numbers= 13:15
The final ratio = 14:11
Cost of first article is raised by Rs. 14
The cost of second article is raised by 10%.
To find:
The original cost of the articles.
Solution:
Let the original numbers be 13x and 15x.
Cost of first article is raised by Rs. 14.
Let the final cost be 14y and 11y.
13x + 14 = 14y- equation 1
15x + 10% of 15x = 11y
15x + 1.5x = 11y
16.5x = 11y
y = 16.5x /11
Put this value in equation 1:
13x + 14 = 14*16.5x/11
13x + 14 = 21x
21x- 13x = 14
8x = 14
x = 14/ 8
x = 1.75
Cost of first article = 13x = Rs. 22.75
Cost of second article = Rs. 26.25
Therefore the original cost of articles is Rs. 22.75 and Rs. 26.25.
SOLUTION
GIVEN
- The ratio of cost of two articles was 13 : 15
- 4 years later when the cost of the first had risen by Rs. 14 and that of the second by 10%
- The ratio of their cost become 14 : 11
TO DETERMINE
The original cost
EVALUATION
Here it is given that the ratio of cost of two articles was 13 : 15
Let first article cost Rs. 13x and second article costs Rs. 15x
Now it is stated that 4 years later when the cost of the first had risen by Rs. 14 and that of the second by 10%
So the cost of first article becomes
= Rs. ( 13x + 14 )
The cost of second article becomes
So by the given condition
Hence
Original cost of first article
= Rs. ( 13 × 1.75 )
= Rs. 22.75
Original cost of second article
= Rs. ( 15 × 1.75 )
= Rs. 26.25
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