Math, asked by rameenas, 1 year ago

The ratio of David's and Austin's age is 3 : 5 . The sum of their ages is 80.What will be the ratio of their ages after 10 years ?

Answers

Answered by kangnaasingh
1
Let the common factor of their ages be 3x and 5x.

3x+5x=80
8x=80
x=80/8
x=10

age after 10 years,
3x+10 and 5x+10
3*10+10 and 5*10+10
40 years and 60 years

Answered by mysticd
0
Hi ,

Let

at present
_________

Ratio of Devid's and Austin's ages

= 3 : 5

Let

David's age = 3x years

Austin's age = 5x years

Sum of their ages = 80

3x + 5x = 80

8x = 80

x = 80 / 8

x = 10

Therefore ,

Devid's age = 3x

= 3 × 10

= 30 years

Austin's age = 5x

= 5 × 10

= 50years

After 10 years
___________

Devid's age would be = 30 + 10

= 40 years

Austin's age would be = 50 + 10

= 60 years

I hope this helps you.

:)
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