Question

The ratio of de broglie wavelength of proton and alpha particle

Answer 1

hope this will help you...

Answer 2

$\huge \sf Alpha \: particles$

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★Since, de Broglie wavelength is given by

$\huge\tt \red{\lambda=\frac{h} {p} }$

Here, p is momentum of particle

Also know that

★Kinetic Energy :

$\huge\tt \orange{K=\frac{p^2} {2m}}$

If we solve,

$\large\tt{\lambda=\frac{h} {\sqrt{2mK} } }$

Here, we can clearly see that de Broglie wavelength is inversely proportional to square root of their masses.

Therefore, the mass of proton $\large\tt{^1_1H}$

H is 1836 times more than an electron and mass of alpha particle $\large\tt{^4_2H}$

H four times that of proton.

Therefore alpha particles have higher wavelength.