Physics, asked by niharikaharsh5, 7 months ago

The ratio of distance traveled by a body falling from rest in the fourth
and fifth second is​

Answers

Answered by mallickmadhumita47
0

Answer:

So the ratio of displacements is − g / 2 : − 3 g / 2 : − 5 g / 2 or simply 1:3:5.] What will be the ratio of the distance moved by a freely falling body from rest in the 4th and 5th seconds of its journey?

Answered by AranyaSen
1

Answer:

4th:5th=7:9

Explanation:

By Gallileo's law

If a body starting from rest mives with uniform acceleration then displacement(distance) in regular intervals is in the ratio 1:3:5:7:9 and so on

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