Question

the ratio of distance travelled by a freely body 2nd s and 3rd s is _________ 10-1. with solution​

Answer 1

Answer:

1:3:5

Explanation:

Initial speed of the body is zero i.e.  u=0

Distance traveled in t  

th

 second is given by    S  

t  

th

 

​

=u+  

2

a

​

(2t−1)

⟹ S  

t  

th

 

​

=  

2

a

​

(2t−1)       (∵u=0)

So, distance traveled in first second,    S  

1

​

=  

2

a

​

(2×1−1)=  

2

a

​

 

So, distance traveled in 2nd second,    S  

2

​

=  

2

a

​

(2×2−1)=  

2

3a

​

 

So, distance traveled in 3rd second,    S  

3

​

=  

2

a

​

(2×3−1)=  

2

5a

​

 

⟹ S  

1

​

:S  

2

​

:S  

3

​

=1:3:5