Question

The ratio of distance travelled by body and displacement is

Answer 1

Distance traveled by a free a free falling body in nth second = distance traveled in n secs−distance traveled in n−1 secs.

=0∗n+ 21

gn 2 −0∗(n−1)+ 21 g(n−1) 2

= 2g (n 2 −(n 2 +1−2n))

= 2g (2n−1)

ratio of distance traveled in 4th sec. to 3rd sec = 2×3−1/2×4−1

=57