Question

The ratio of distances of satellites A and B above the earth's surface is 1.4 :1, then the ratio of energies of satellites B and A will be -
A.1.4 : 1
B.2 : 1
C.1 : 3
D.4 : 1

Answer 1

Answer:

ANSWER

Total energy T.E.=

2r

−GMm

Now Total energy for p, T

p

=

2r

p

−GMm

similarly T

q

=

2r

q

−GMm

Taking the ratio we get,

T

q

T

p

=

2r

p

−GMm

×

−GMm

2r

q

=

r

p

r

q

. Given

r

q

r

p

=3.

Therefore,

T

q

T

p

=

3

1

Answer 2

ANSWER

Total energy T.E.=2r−GMm

Now Total energy for p, T

p=2rp−GMm

similarly

Tq=2rq−GMm

Taking the ratio we get,

TqTp=.2rp−GMm×−GMm2rq=rprq

. Given

r

q

r

p

=3.

Therefore,

T

q

T

p

=

3

1