Math, asked by anandthaniyilar4748, 4 months ago

The ratio of dogs and Cats at another party is 5:7, there are 8 more dogs than cats, how many cats are there

Answers

Answered by peddintiganesh154

0

Answer:

Simple algebraic simultaneous equations: D=number of dogs, C=number of cats

D/C=5/7 the ratio of dogs to cats

D=C+8 there are 8 more dogs than cats

Let’s solve for D in our first equation: D=5C/7

Substitute for D in our second equation: 5C/7=C+8 or 5C=7C+56; or 2C=56

Therefore, C=28.

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