Math, asked by pikachu8013, 19 days ago

The ratio of efficiency of ajay and sneha is 6: 5. The ratio of number of days taken by prabha to sneha is 3: 2. Ajay takes 3 days less than sneha, when ajay and sneha complete the work individually. Prabha and sneha started the work and left after 3 days. The number of days taken by ajay to finish the remaining work is?.

Answers

Answered by siddhikhile
0

the ratio of number of days taken by Ajay and Sneha =5:6

and the ratio of number of days taken by Prabha and Sneha 3:2

ratio of number of days taken by Ajay :Sneha:Prabha :5:6:9

i.e. 5x,6x,9x

according the condition

6x-5x=3day

X=3day

therefore,Ajay=15day ,Sneha=18 day and Prabha=27day

but work

done by Prabha and Sneha in one days =1/18+1/27=3+2/54=5/54

and Prabha and Sneha 3day work =5/54*3=5/18

rest of work =13/18

therefore, the number of days taken by Ajay the remaining work =13/18*15

=65/6

=10 5/6 days

Similar questions