Question

The ratio of electric field and potential (e/v) at midpoint of electric dipole, for which separation is ell is:

Answer 1

Answer:

Infinity

Explanation:

E=2Kq/(l/2)2

V=0

Therefore E/V=infinity

Answer 2

The ratio of electric field and potential at the midpoint of an electric dipole is infinity (∞).

• Potential at mid-point due to both negative and positive charge,

V′ = (−V) + (V) = 0

• Physically, the resultant force is always at right angles to the direction of movement if a test charge is moved from the midpoint along the line that bisects the line connecting the charges.
• So, it is possible to transfer the test charge to infinity without exerting any effort. V = the amount of work required to transport a test charge from that location to infinity, hence V = 0.

So, the ratio of the electric field to the potential at the midpoint,

e/V'= e/0 = ∞

Hence, the ratio of electric field and potential at the midpoint of an electric dipole is infinity (∞).

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