Question

The ratio of electric field intensity at distance 5 cm to that at 10 cm from a point charge 3Q in air is
A) 2:1
B) 1:2
C) 1:4
D) 4:1​

Answer 1

Answer:

d) 4:1

Explanation:

E is inversely proportional to

$\frac{1}{ {r}^{2} }$

$\frac{e1}{e2} = \frac{ {r2}^{2} }{ {r1}^{2} }$

$\frac{ {10}^{2} }{ {5}^{2} } = 100 \div 25 = 4$

plz mark the Brainliast....

Answer 2

The answer is 1:4.......