Question

The ratio of electric field intensity due to infinite sheet of charge and parallel oppositely charged plates is
(a) 1:2
(b) 2:1
(c) 2:3
(d) 3:2
(correct answer is a. how?)​

Answer 1

Answer:

The electric field inetensity due to the long sheet of charge is given by:

E

1

=E

2

=

2ϵ

0

σ

The electriic field intensity between plates

E

in

=E

1

−E

2

⇒E=0

The electric field intensity outside plates

E

out

=E

1

+E

2

⇒E=

ϵ

0

σ

Answer 2

Answer: The correct answer is A) 1:2

Explanation:

Now according to Gauss Law,

In the case of an infinite sheet of charge,

E1 = σ / 2μ0

And in case of oppositely charged parallel plates,

E2 = σ / μ0

then,

E1/E2 = σ/2μ0 / σ/μ0

Cancel  σ and μ0,

E1/E2 = 1/2 = 1:2