Physics, asked by aruja17, 11 months ago

the ratio of electric force (fe) to gravitational force acting between two electrons will be ​

Answers

Answered by harsh3374chauhan
6

F = (ke^2) /r^2 (electric force)

F = (Gme^2)/r^2 ( gravitational force)


aruja17: rong answer
harsh3374chauhan: what's wrong
harsh3374chauhan: it's just formula
harsh3374chauhan: I have not given the answer
aruja17: Ok
harsh3374chauhan: ya
Answered by vinay7860
5
Here is your answer.

The gravitational force is given by Newton’s law of universal gravitation to be:

Fg=Gm1m2r2

In this case, the gravitational force between an electron and a proton would be:

Fg=6.67×10−11×9.10938×10−31×1.67262×10−27r2

The electrostatic force of attraction is given by Coulomb’s law as:

Fe=kq1q2r2

In this case, the electrostatic force between an electron and a proton with the medium of separation being air would be:

Fe=−9.0×109×(1.6×10−19)2r2

Therefore, the ratio of the magnitudes of the gravitational force to electrostatic force would be:

ratio=6.67×10−11×9.10938×10−31×1.67262×10−27r29.0×109×(1.6×10−19)2r2

Now because the distance of separation is the same,

ratio=6.67×10−11×9.10938×10−31×1.67262×10−279.0×109×(1.6×10−19)2

ratio=101.62766×10−6923.04×10−29

ratio=4×10−40

I hope my answer is help you.

B brainly

aruja17: no rong
aruja17: no 4×10-42
vinay7860: ok sorry
vinay7860: I edit my answer
vinay7860: ok
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