Question

The ratio of electrostatic force between 2 point charges in air and in a medium of dielectric constant K is?

Answer 1

K:1

Explanation:

As per Coulumb's law,

F = $k \frac{q_{1} q_{2}}{r^2}$

where,

F is the force,

q_{1} &q_{2} are the charges over the allowance of free space and

r is the distance

To determine,

Force of air = $q_{1} &q_{2}$/4π∈_{0} r^2 ...(i)

To determine,

Force in dilectric constant:

$F_{d}$ = = $q_{1} &q_{2}$/4πK∈_{0}r^2 ...(ii)

On dividing (i) by (ii), we get;

$F_{air}/F_{d}$ = K/1

Thus, the ratio among the two spheres is K:1.

Learn more: Dielectric constant

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