Question

The ratio of energies of hydrogen atom in its first excited state to third excited state is

Answer 1

Answer:

Answer :

C

Solution :

First excited state i.e., second orbit `(n = 2)` <br> Second excited state i.e., third orbit `(n = 3)` <br> `:. E = -(13.6)/(n^(2)) rArr (E_(2))/(E_(3)) = ((3)/(2))^(2) = (9)/(4)`

Explanation:

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Answer 2

Answer:

here is your answer

Explanation:

1st excited state corresponds to n=2

2nd excited state corresponds to n=3

∴ E1/E2 = (n2)2/(n1)2 = 9/4

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