Question

The ratio of energy of a photon of 2000a wavelength radiation to that of 4000a radiation is

Answer 1

energy E inversely proportional to wavelength...
as
$e = hc \div lambda$
lambda=wavelength
E1/E2= lambda 2/lambda 1

E1/E2=4000 a/2000 a
=2/1
=2:1

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Answer 2

Answer:

Concept:

In physics, radiation is the transfer of energy in the waves or particles over space or through a material medium. Radio waves, microwaves, infrared, visible light, ultraviolet, x-rays, and gamma radiation are examples of electromagnetic radiation. Radiation is energy that comes from a source and flows through space at the speed of light. This energy is coupled with an electric field and a magnetic field, and it has wave-like qualities.

Given:

The energy of a photon with a wavelength of 2000a compared to a photon with a wavelength of 4000a is

find:

Find the answer for the given question

Answer:

=> The emission or transfer of energy in the waves or particles across space or a material medium is known as radiation. The highest-energy radiation includes ultraviolet light, x-rays, and gamma rays. X-rays and gamma rays have a high energy level. They can remove electrons from atoms when they engage with them, causing the atom to become ionized.

$E_{1}=\frac{h_{c} }{lamda1}$

$E_{2}=\frac{h_{c} }{lamda2}$

$\frac{E_{1} }{E_{2} } =\frac{h_{c} }{lamda1}$ × $\frac{lamda2}{h_{c} }$

$=\frac{lamda2}{lamda1}$

$=\frac{4000}{2000}$

$=2$

∴ The radiation is $2$

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